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The molar mass of Ca (PO ) is 310.2 g mol
CHEMISTRY · Subjective · AP · Chemistry · Equilibrium · Equilibrium
Problem
The molar mass of Ca
3
_3
3
(PO
4
_4
4
)
2
_2
2
is 310.2 g mol
−
1
^{-1}
−
1
. If its solubility in water at 25 °C is found experimentally to be 6.5 × 10
−
4
^{-4}
−
4
g L
−
1
^{-1}
−
1
, calculate the value of
K
s
p
K_{sp}
K
s
p
for Ca
3
_3
3
(PO
4
_4
4
)
2
_2
2
at this temperature.
Related theory
Equilibrium
Chemical Equilibrium
Solubility product
Solubility Equilibria
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