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In a reactor, 2 kg of fuel is fully used up in 30 days
PHYSICS · Subjective · CBSE · Physics · Nuclei · Nuclei
Problem
In a reactor, 2 kg of
92
235
U
{}_{92}^{235}\text{U}
92
235
U
fuel is fully used up in 30 days. The energy released per fission is 200 MeV. Given that the Avogadro number,
N
=
6.023
×
10
26
N = 6.023 \times 10^{26}
N
=
6.023
×
1
0
26
per kilo mole and
1
eV
=
1.6
×
10
−
19
J
1 \text{ eV} = 1.6 \times 10^{-19} \text{ J}
1
eV
=
1.6
×
1
0
−
19
J
. The power output of the reactor is close to:
Related theory
Mass-Energy Equivalence
Nuclear Fission
Nuclear Reactions
Nuclear fission and fusion
Nuclear physics
Atomic Structure
Nuclei
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