Show that, for every acute angle , 1- 1+ = ( - )^ 2…

MATHEMATICS · Subjective · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Show that, for every acute angle θ\theta, 1−sin⁡θ1+sin⁡θ=(sec⁡θ−tan⁡θ)2.\frac{1-\sin \theta}{1+\sin \theta}=\left(\sec \theta-\tan \theta\right)^{2}.

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