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If 7x+1 (x+2)(x-3)(x+4) = A x+2 + B x-3 + C x+4
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
If
7
x
+
1
(
x
+
2
)
(
x
−
3
)
(
x
+
4
)
=
A
x
+
2
+
B
x
−
3
+
C
x
+
4
,
\frac{7x+1}{(x+2)(x-3)(x+4)}=\frac{A}{x+2}+\frac{B}{x-3}+\frac{C}{x+4},
(
x
+
2
)
(
x
−
3
)
(
x
+
4
)
7
x
+
1
=
x
+
2
A
+
x
−
3
B
+
x
+
4
C
,
then the value of
A
A
A
is (a)
−
13
10
-\dfrac{13}{10}
−
10
13
(b)
3
2
\dfrac{3}{2}
2
3
(c)
13
10
\dfrac{13}{10}
10
13
(d)
7
10
\dfrac{7}{10}
10
7
Related theory
Integration Techniques
Integration by partial fractions
Integrals
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