The diameter of a virus is given as

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Problem

The diameter of a virus is given as 1.25×10−8 m1.25 \times 10^{-8}\,\text{m}. Express this diameter in nanometres (nm) in standard decimal form. (1 nm=10−9 m)(1\,\text{nm}=10^{-9}\,\text{m}) (a) 125 nm125\,\text{nm} (b) 1.25 nm1.25\,\text{nm} (c) 12.5 nm12.5\,\text{nm} (d) 0.125 nm0.125\,\text{nm}

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