In the fission process use the atomic masses below to answer the following

PHYSICS · Multi-part · CBSE · Physics · Nuclei · Nuclei

Problem

In the fission process

^{235}_{92}\text{U} + n \to ^{141}_{56}\text{Ba} + ^{92}_{36}\text{Kr} + 3n

use the atomic masses below to answer the following.

\begin{aligned} \!m(^{235}\text{U}) &= 235.043929\,\text{u},\\ \!m(n) &= 1.008665\,\text{u},\\ \!m(^{141}\text{Ba}) &= 140.914411\,\text{u},\\ \!m(^{92}\text{Kr}) &= 91.926160\,\text{u} \end{aligned}

Given:

1\,\text{u} = 931.5\,\text{MeV}/c^{2}

and

1\,\text{eV}=1.602\times10^{-19}\,\text{J}

. (a) Calculate the energy released per fission in MeV. (b) Express this energy in joules.