For the ellipse x^ 2 49 + y^ 2 25 =1

MATHEMATICS · Subjective · CBSE · Mathematics · Conic Sections · Conic Sections

Problem

For the ellipse x249+y225=1,\frac{x^{2}}{49}+\frac{y^{2}}{25}=1, find the set of all real numbers tt for which the point (5,t)(5,t) lies outside the ellipse. Express your answer as an inequality in tt.

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