A laboratory chemist wishes to produce compound D from simple reagents P and Q

CHEMISTRY · Multi-part · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

A laboratory chemist wishes to produce compound D from simple reagents P and Q. Three elementary reactions that can occur in the reaction vessel are listed with their standard Gibbs free energy changes at 298 K. (1) P+Q→RΔG1∘=+22 kJ mol−1P + Q \to R \quad \Delta G^\circ_1 = +22\,\text{kJ}\,\text{mol}^{-1} (2) R→SΔG2∘=+15 kJ mol−1R \to S \quad \Delta G^\circ_2 = +15\,\text{kJ}\,\text{mol}^{-1} (3) S→DΔG3∘=−60 kJ mol−1S \to D \quad \Delta G^\circ_3 = -60\,\text{kJ}\,\text{mol}^{-1} Through appropriate choice of catalysts, the chemist can promote or suppress any of these steps. The goal is to design a pathway that yields D from P and Q with the most favorable overall thermodynamics. Answer the following questions. (1) Part 1: (a) Propose a sequence of the elementary reactions (choose any subset, in any order, and specify stoichiometric coefficients if a reaction must occur more than once) that converts P+QP + Q into DD while eliminating all intermediates. (2) Part 2: (b) For your proposed pathway, calculate the net standard Gibbs free energy change. Show all reasoning, including any stoichiometric scaling you performed. (3) Part 3: (c) Justify why your chosen sequence is thermodynamically preferable to any alternative combination that also yields DD from P+QP + Q using the given elementary reactions. (4) Part 4: (d) If experimental results show that intermediate SS accumulates instead of being fully converted to DD, explain how this observation affects the actual free-energy profile of the pathway and suggest one practical method to overcome the issue.

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