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For a continuous function on
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
For a continuous function
p
p
p
on
[
0
,
9
]
[0,9]
[
0
,
9
]
, the following values are known:
∫
0
3
p
(
x
)
d
x
=
k
,
\displaystyle \int_{0}^{3} p(x)\,dx = k,
∫
0
3
p
(
x
)
d
x
=
k
,
∫
3
6
p
(
x
)
d
x
=
2
k
+
1
,
\displaystyle \int_{3}^{6} p(x)\,dx = 2k + 1,
∫
3
6
p
(
x
)
d
x
=
2
k
+
1
,
∫
6
9
p
(
x
)
d
x
=
1
−
k
,
\displaystyle \int_{6}^{9} p(x)\,dx = 1 - k,
∫
6
9
p
(
x
)
d
x
=
1
−
k
,
∫
0
9
p
(
x
)
d
x
=
4
k
−
2.
\displaystyle \int_{0}^{9} p(x)\,dx = 4k - 2.
∫
0
9
p
(
x
)
d
x
=
4
k
−
2.
What is the value of
k
k
k
? (a)
k
=
3
k = 3
k
=
3
(b)
k
=
1
k = 1
k
=
1
(c)
k
=
2
k = 2
k
=
2
(d)
k
=
−
1
k = -1
k
=
−
1
Related theory
Properties of Definite Integrals
Accumulation Concepts
Integrals
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