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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Matrices · Matrices
Problem
If
[
1
−
tan
θ
tan
θ
1
]
[
1
tan
θ
−
tan
θ
1
]
−
1
=
[
a
−
b
b
a
]
\begin{bmatrix}1&-\tan\theta\\\tan\theta&1\end{bmatrix}\begin{bmatrix}1&\tan\theta\\-\tan\theta&1\end{bmatrix}^{-1}=\begin{bmatrix}a&-b\\b&a\end{bmatrix}
[
1
tan
θ
−
tan
θ
1
]
[
1
−
tan
θ
tan
θ
1
]
−
1
=
[
a
b
−
b
a
]
, then: (a)
a
=
b
=
1
a=b=1
a
=
b
=
1
(b)
a
=
cos
2
θ
,
b
=
sin
2
θ
a=\cos2\theta,\ b=\sin2\theta
a
=
cos
2
θ
,
b
=
sin
2
θ
(c)
a
=
sin
2
θ
,
b
=
cos
2
θ
a=\sin2\theta,\ b=\cos2\theta
a
=
sin
2
θ
,
b
=
cos
2
θ
(d)
a
=
1
,
b
=
sin
2
θ
a=1,\ b=\sin2\theta
a
=
1
,
b
=
sin
2
θ
Related theory
Trigonometric Identities
Trigonometric Functions
Determinants
Matrices
Matrix operations
Multiplication of matrices
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