Explain briefly why the definite integral exists when f(x)= cases x^ 2 -9 x-3 , & x 3

MATHEMATICS · Subjective · AP · Calculus AB · Limits and Continuity · Limits and Continuity

Problem

Explain briefly why the definite integral ∫15f(x) dx\displaystyle\int_{1}^{5} f(x)\,dx exists when f(x)={x2−9x−3,x≠3,undefined,x=3.f(x)=\begin{cases}\dfrac{x^{2}-9}{x-3}, & x\neq 3,\\ \text{undefined}, & x=3. \end{cases}

Related theory

Browse the problem library