Consider an arithmetic progression (A.P.) whose first term is and common difference is

MATHEMATICS · Multi-part · CBSE · Mathematics · Arithmetic Progressions · Arithmetic Progressions

Problem

Consider an arithmetic progression (A.P.) whose first term is aa and common difference is dd. Let SnS_n denote the sum of its first nn terms. (i) Prove that Sn=n2[2a+(n−1)d]S_n=\dfrac{n}{2}\bigl[2a+(n-1)d\bigr]. Clearly state every algebraic step used. (ii) Show that the nnth term ana_n of the same A.P. can be written as an=Sn−Sn−1a_n=S_n-S_{n-1}. Explain why this relation holds. (iii) Using the result of part (ii), obtain ana_n in terms of aa, dd and nn and verify that it matches the well-known expression an=a+(n−1)da_n=a+(n-1)d. Discuss briefly how parts (i) and (ii) together justify the consistency of the two formulas for an A.P.

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