Consider an arithmetic progression (A.P.) whose first term is a and common difference is d. Let Sn denote the sum of its first n terms.
(i) Prove that Sn=2n[2a+(n−1)d]. Clearly state every algebraic step used.
(ii) Show that the nth term an of the same A.P. can be written as an=Sn−Sn−1. Explain why this relation holds.
(iii) Using the result of part (ii), obtain an in terms of a, d and n and verify that it matches the well-known expression an=a+(n−1)d. Discuss briefly how parts (i) and (ii) together justify the consistency of the two formulas for an A.P.