The dissolution of sodium chloride in water at can be described by the sequence of…

CHEMISTRY · Multi-part · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

The dissolution of sodium chloride in water at 298 K298\,\text{K} can be described by the sequence of elementary processes below. All values refer to one mole of NaCl\text{NaCl}. Process I: NaCl(s)→Na+(g)+Cl−(g)\text{NaCl(s)} \rightarrow \text{Na}^+(g) + \text{Cl}^-(g)  ΔSI∘=+240.0 J mol−1 K−1\Delta S^\circ_I = +240.0\,\text{J mol}^{-1}\,\text{K}^{-1} Process II: Na+(g)→Na+(aq)\text{Na}^+(g) \rightarrow \text{Na}^+(aq)  ΔSII∘=−155.0 J mol−1 K−1\Delta S^\circ_{II} = -155.0\,\text{J mol}^{-1}\,\text{K}^{-1} Process III: Cl−(g)→Cl−(aq)\text{Cl}^-(g) \rightarrow \text{Cl}^-(aq)  ΔSIII∘=−180.0 J mol−1 K−1\Delta S^\circ_{III} = -180.0\,\text{J mol}^{-1}\,\text{K}^{-1} Consider the overall dissolution reaction: NaCl(s)→Na+(aq)+Cl−(aq)\text{NaCl(s)} \rightarrow \text{Na}^+(aq) + \text{Cl}^-(aq) (a) Calculate the standard entropy change ΔSdiss∘\Delta S^\circ_{\text{diss}} for the dissolution of NaCl(s)\text{NaCl(s)} at 298 K298\,\text{K}. (b) The standard enthalpy change for this dissolution is ΔHdiss∘=+3.9 kJ mol−1\Delta H^\circ_{\text{diss}} = +3.9\,\text{kJ mol}^{-1}. Using the sign and relative magnitudes of ΔHdiss∘\Delta H^\circ_{\text{diss}} and your calculated ΔSdiss∘\Delta S^\circ_{\text{diss}}, determine whether the dissolution of NaCl(s)\text{NaCl(s)} is spontaneous at 298 K298\,\text{K}. Justify your answer quantitatively. (c) Predict qualitatively how increasing the temperature would affect the spontaneity of NaCl\text{NaCl} dissolution, based on the thermodynamic quantities involved.

Related theory

Browse the problem library