An object is placed in front of a concave mirror of focal length

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Geometric Optics · Geometric Optics

Problem

An object is placed 40 cm40\,\text{cm} in front of a concave mirror of focal length 20 cm20\,\text{cm}. Using the Cartesian sign convention, the image distance vv is: (a) +403 cm+\dfrac{40}{3}\,\text{cm} (b) −40 cm-40\,\text{cm} (c) +40 cm+40\,\text{cm} (d) −20 cm-20\,\text{cm}

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