A spherical lump of a fissile material emits on average neutrons per fission

PHYSICS · Single correct · CBSE · Physics · Nuclei · Nuclei

Problem

A spherical lump of a fissile material emits on average ν=2.4\nu = 2.4 neutrons per fission. The probability that a neutron escapes without causing further fission is approximated by P=e−R/10P = e^{-R/10}, where RR (in cm) is the sphere’s radius and the neutron mean free path is 10 cm. Criticality is reached when k=ν(1−P)=1k = \nu (1-P) = 1. The minimum radius required for criticality is closest to (a) 12 cm12\ \text{cm} (b) 5.4 cm5.4\ \text{cm} (c) 3 cm3\ \text{cm} (d) 8.1 cm8.1\ \text{cm}

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