A proton ( ) enters a region of uniform magnetic field of magnitude with a speed of .

PHYSICS · Multi-part · CBSE · Physics · Moving Charges and Magnetism · Moving Charges and Magnetism

Problem

A proton (q=+1.6×10−19 Cq=+1.6\times10^{-19}\,\text{C}) enters a region of uniform magnetic field of magnitude 0.20 T0.20\,\text{T} with a speed of 2.5×106 m s−12.5\times10^{6}\,\text{m}\,\text{s}^{-1}. (a) The proton’s velocity is initially perpendicular to the magnetic field lines. Calculate the magnitude of the magnetic force acting on the proton at that instant. (b) The same proton now moves exactly parallel to the magnetic field lines with the same speed. Determine the magnitude of the magnetic force in this case. (c) Finally, the proton’s velocity makes an angle of 30∘30^\circ with the field lines. Without performing a numerical calculation, state whether the magnetic force magnitude will be greater than, less than, or equal to the value found in part (a). Justify your answer qualitatively.

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