The fission reaction the following nuclear masses (in u): , , ,

PHYSICS · Single correct · CBSE · Physics · Nuclei · Nuclei

Problem

The fission reaction

^{235}_{92}\mathrm{U}+^{1}_{0}\mathrm{n}\;\longrightarrow\;^{141}_{56}\mathrm{Ba}+^{92}_{36}\mathrm{Kr}+3\,^{1}_{0}\mathrm{n}

uses the following nuclear masses (in u):

^{235}\mathrm{U}=235.043929

^{141}\mathrm{Ba}=140.914411

^{92}\mathrm{Kr}=91.926156

^{1}\mathrm{n}=1.008665

. Calculate the energy released per mole of

^{235}\mathrm{U}

that undergoes this fission reaction. Give your answer to one significant figure in

\text{kJ mol}^{-1}

\bigl(1\,\text{u}=931.5\,\text{MeV}/c^{2},\;1\,\text{MeV}=1.602\times10^{-13}\,\text{J},\;N_{A}=6.022\times10^{23}\,\text{mol}^{-1}\bigr)

(a)

1.7\times10^{12}\,\text{kJ mol}^{-1}

(b)

1.7\times10^{10}\,\text{kJ mol}^{-1}

(c)

1.7\times10^{8}\,\text{kJ mol}^{-1}

(d)

1.7\times10^{13}\,\text{kJ mol}^{-1}