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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
[
1
log
x
−
1
(
log
x
)
2
]
d
x
=
\int\left[\frac{1}{\log x}-\frac{1}{(\log x)^2}\right]dx=
∫
[
l
o
g
x
1
−
(
l
o
g
x
)
2
1
]
d
x
=
(a)
1
log
x
+
C
\frac{1}{\log x}+C
l
o
g
x
1
+
C
(b)
x
log
x
+
C
\frac{x}{\log x}+C
l
o
g
x
x
+
C
(c)
x
(
log
x
)
2
+
C
+
C
\frac{x}{(\log x)^2}+C+C
(
l
o
g
x
)
2
x
+
C
+
C
(d) None of these
Related theory
Logarithmic Differentiation
Advanced Differentiation
Antiderivatives
Integration Techniques
Integration by parts
Integrals
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