If , where , then the value of…

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

If F(x)=∫1xf(t) dtF(x)=\int_1^x f(t)\,dt, where f(t)=∫1t21+u4u duf(t)=\int_1^{t^2}\frac{\sqrt{1+u^4}}{u}\,du, then the value of F′′(2)F''(2) equals (1) 7417\frac{7}{4\sqrt{17}} (2) 1517\frac{15}{\sqrt{17}} (3) 257\sqrt{257} (4) 151768\frac{15\sqrt{17}}{68}

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