If , where , then the value of…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
If F(x)=∫1xf(t)dt, where f(t)=∫1t2u1+u4du, then the value of F′′(2) equals
(1) 4177
(2) 1715
(3) 257
(4) 681517
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