Let be a twice–differentiable function whose first derivative is given by h'(x)=3 x -…

MATHEMATICS · Multi-part · A Level · Mathematics · Integration · Integration

Problem

Let hh be a twice–differentiable function whose first derivative is given by h′(x)=3x−2x2+7sin⁡x+e5x,x>0.h'(x)=3\sqrt{x}-\frac{2}{x^{2}}+7\sin x+e^{5x}, \qquad x>0. It is known that h(1)=4h(1)=4. (a) Determine the general expression for h(x)h(x). (b) Find the particular form of h(x)h(x) that satisfies the given initial condition. (c) Using your result in part (b), write the equation of the tangent line to the graph of hh at x=1x=1. (d) Show that h′′(x)=32x1/2+4x3+7cos⁡x+5e5xh''(x)=\dfrac{3}{2x^{1/2}}+\dfrac{4}{x^{3}}+7\cos x+5e^{5x} and briefly interpret the sign of h′′(1)h''(1) in terms of the concavity of the graph at x=1x=1.

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