If I_m = ( x + x)^m

MATHEMATICS · Subjective · CBSE · Mathematics · Integrals · Integrals

Problem

If Im=∫(sin⁡x+cos⁡x)m dxI_m = \int (\sin x + \cos x)^m \, dx, then show that mIm=(sin⁡x+cos⁡x)m−1⋅(sin⁡x−cos⁡x)+2(m−1)Im−2m I_m = (\sin x + \cos x)^{m-1} \cdot (\sin x - \cos x) + 2 (m-1) I_{m-2}.

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