Show that the two values are the roots of the equation

MATHEMATICS · Subjective · CBSE · Mathematics · Quadratic Equations · Quadratic Equations

Problem

Show that the two values x=−b±b2−4ac2ax = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} are the roots of the equation ax2+bx+c=0ax^2 + bx + c = 0, where aa, bb, and cc are constants, and aa and cc are nonzero.

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