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I = _0^1 8 (1+x) (1+x^2) dx
MATHEMATICS · Subjective · CBSE · Mathematics · Integrals · Integrals
Problem
I
=
∫
0
1
8
log
(
1
+
x
)
(
1
+
x
2
)
d
x
I = \int_0^1 \frac{8 \log(1+x)}{(1+x^2)} dx
I
=
∫
0
1
(
1
+
x
2
)
8
lo
g
(
1
+
x
)
d
x
Related theory
Properties of Definite Integrals
Accumulation Concepts
Integration Techniques
Standard trigonometric integrals
Integration using trigonometric identities
Integrals
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