Consider the equation with .

MATHEMATICS · Multi-part · A Level · Mathematics · Trigonometry · Trigonometry

Problem

Consider the equation 2sin⁡2θ−3sin⁡θ+1=02\sin^{2}\theta - 3\sin\theta + 1 = 0 with 0≤θ<2π0 \le \theta < 2\pi. (i) Treating sin⁡θ\sin\theta as a variable, solve the quadratic equation and obtain the possible numerical values of sin⁡θ\sin\theta. (ii) For each admissible value of sin⁡θ\sin\theta, determine all corresponding values of θ\theta within 0≤θ<2π0 \le \theta < 2\pi.

Related theory

Browse the problem library