Using the value obtained in Question 3 (about 17.6 MeV per reaction)

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Problem

Using the value obtained in Question 3 (about 17.6 MeV per reaction), the energy released by one mole of 2 ⁣H+3 ⁣H^{2}\!\mathrm{H}+{}^{3}\!\mathrm{H} fusion reactions is approximately (take NA=6.02×1023 mol−1N_A = 6.02\times10^{23}\,\text{mol}^{-1} and 1 eV=1.60×10−19 J1\,\text{eV}=1.60\times10^{-19}\,\text{J}) (a) 1.7×1013 J1.7\times10^{13}\,\text{J} (b) 1.7×1012 J1.7\times10^{12}\,\text{J} (c) 1.7×1010 J1.7\times10^{10}\,\text{J} (d) 8.8×1011 J8.8\times10^{11}\,\text{J}

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