When a 92235U nucleus absorbs a slow neutron it splits into 56141Ba, 3692Kr and three free neutrons.
The nuclear masses involved are:
92235U : 235.04393u56141Ba : 140.91440u3692Kr : 91.92615u
Neutron : 1.00866u1u=931.5MeV/c2.
(i) Calculate the total mass defect for one fission event.
(ii) Determine the energy released per fission in MeV.
(iii) Express this energy in joules.
(iv) If a reactor produces 3.0×1020 such fissions per second, estimate the power output in megawatts.