The electric field of a plane electromagnetic wave propagating along the direction in…

PHYSICS · Single correct · CBSE · Physics · Electromagnetic Waves · Electromagnetic Waves

Problem

The electric field of a plane electromagnetic wave propagating along the xx direction in vacuum is E⃗=E0j^cos⁡(ωt−kx)\vec{E} = E_0 \hat{j} \cos(\omega t - kx) . The magnetic field B⃗\vec{B} , at the moment t=0t = 0 is : (1) B⃗=E0μ0ϵ0cos⁡(kx)k^\vec{B} = \frac{E_0}{\sqrt{\mu_0 \epsilon_0}} \cos(kx) \hat{k} (2) B⃗=E0μ0ϵ0cos⁡(kx)j^\vec{B} = E_0 \sqrt{\mu_0 \epsilon_0} \cos(kx) \hat{j} (3) B⃗=E0μ0ϵ0cos⁡(kx)k^\vec{B} = E_0 \sqrt{\mu_0 \epsilon_0} \cos(kx) \hat{k} (4) B⃗=E0μ0ϵ0cos⁡(kx)j^\vec{B} = \frac{E_0}{\sqrt{\mu_0 \epsilon_0}} \cos(kx) \hat{j}

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