A nucleus of selenium-79 undergoes a two-step decay sequence

PHYSICS · Multi-part · CBSE · Physics · Nuclei · Nuclei

Problem

A nucleus of selenium-79 undergoes a two-step decay sequence. First it experiences a single β−\beta^{-} decay to form nucleus XX. The resulting nucleus XX then undergoes an α\alpha decay to form the final nucleus YY. 3479Se  ⟶  X  →α  Y^{79}_{34}\text{Se}\;\longrightarrow\;X\;\xrightarrow[]{\alpha}\;Y (a) Write the balanced nuclear equation for the β−\beta^{-} decay of 3479Se^{79}_{34}\text{Se}, including all emitted particles. (b) Write the balanced nuclear equation for the subsequent α\alpha decay of nucleus XX to produce nucleus YY, including all emitted particles. (c) Combine your results from parts (a) and (b) into a single overall nuclear equation that shows the net transformation from 3479Se^{79}_{34}\text{Se} to YY, listing every particle emitted in the sequence. (d) Demonstrate explicitly that your overall equation conserves both nucleon number and electric charge. (e) State the atomic number and mass number of the final nucleus YY, and describe the net change in atomic number and mass number that occurred between the original selenium nucleus and YY.

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