A laboratory is cultivating a yeast population (in hundreds of cells)

MATHEMATICS · Multi-part · AP · Calculus AB · Differential Equations · Differential Equations

Problem

A laboratory is cultivating a yeast population Y(t)Y(t) (in hundreds of cells). For the first 55 hours the growth of the yeast is uninhibited, and YY satisfies dYdt=k1Y\displaystyle \frac{dY}{dt}=k_1Y with k1>0k_1>0. At t=5t=5 hours, the temperature of the incubator is lowered, and from that moment on the population satisfies dYdt=k2Y\displaystyle \frac{dY}{dt}=k_2Y with k2<0k_2<0. The following observations are recorded: • Y(0)=200Y(0)=200. • Y(5)=3200Y(5)=3200. • Y(8)=2000Y(8)=2000. (a) Determine the numerical value of k1k_1 (in hr−1\text{hr}^{-1}). (b) Obtain an explicit expression for Y(t)Y(t) for 0≤t≤50\le t\le5. (c) Use the data provided for t=5t=5 and t=8t=8 to find the numerical value of k2k_2 (in hr−1\text{hr}^{-1}). (d) Write a piecewise-defined expression for Y(t)Y(t) that is valid for all t≥0t\ge0. (e) Estimate, to the nearest tenth of an hour, the time after t=5t=5 when the yeast population will decline to 500 cells.

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