Calculate the energy released ( ) in MeV for the following fission reaction: Atomic…

PHYSICS · Single correct · A Level · Physics · Nuclear physics · Nuclear physics

Problem

Calculate the energy released (

Q

) in MeV for the following fission reaction:

^{235}_{92}\text{U}+^{1}_{0}\text{n}\;\rightarrow\;^{92}_{36}\text{Kr}+^{141}_{56}\text{Ba}+3\,^{1}_{0}\text{n}

Atomic masses:

^{235}_{92}\text{U}=235.0439\,\text{u}

^{92}_{36}\text{Kr}=91.9262\,\text{u}

^{141}_{56}\text{Ba}=140.9144\,\text{u}

^{1}_{0}\text{n}=1.0087\,\text{u}

Use

1\,\text{u}=931.5\,\text{MeV}/c^{2}

. (a)

211\,\text{MeV}

(b)

17.3\,\text{MeV}

(c)

173\,\text{MeV}

(d)

155\,\text{MeV}