In an infinite geometric progression with first term and common ratio ( )

MATHEMATICS · Single correct · CBSE · Mathematics · Sequences and Series · Sequences and Series

Problem

In an infinite geometric progression with first term aa and common ratio rr (∣r∣<1|r|<1), let SnS_n be the sum of the first nn terms and S∞S_\infty be the sum to infinity. Which of the following expressions equals the remainder Rn=S∞−SnR_n = S_\infty - S_n? (a) arn+11−r\dfrac{a r^{n+1}}{1 - r} (b) a(1−rn)1−r\dfrac{a(1 - r^{n})}{1 - r} (c) arn1−r\dfrac{a r^{n}}{1 - r} (d) arn−11−r\dfrac{a r^{n-1}}{1 - r}

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