A radioactive nucleus decays to a nucleus with a decay constant

PHYSICS · Multi-part · A Level · Physics · Nuclear physics · Nuclear physics

Problem

A radioactive nucleus XX decays to a nucleus YY with a decay constant λx=0.1 s−1\lambda_x = 0.1 \text{ s}^{-1} . YY further decays to a stable nucleus ZZ with a decay constant λy=1/30 s−1\lambda_y = 1/30 \text{ s}^{-1} . Initially, there are only XX nuclei and their number is N0=1020N_0 = 10^{20} . The population of YY nucleus as a function of time is given by NY(t)=(N0λx/(λx−λy)){exp⁡(−λyt)−exp⁡(−λxt)}N_Y(t) = (N_0 \lambda_x / (\lambda_x - \lambda_y)) \{ \exp(-\lambda_y t) - \exp(-\lambda_x t) \} . (1) Set up the rate equations for the populations of XX, YY and ZZ. (2) Find the time at which NYN_Y is maximum (3) determine the populations XX and ZZ at that instant.

Related theory

Browse the problem library