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The reaction has the following atomic masses: , , ,
PHYSICS · Single correct · CBSE · Physics · Nuclei · Nuclei
Problem
The reaction
1
2
D
+
1
3
T
→
2
4
H
e
+
n
^2_1\mathrm D + ^3_1\mathrm T \rightarrow {}^4_2\mathrm He + n
1
2
D
+
1
3
T
→
2
4
H
e
+
n
has the following atomic masses:
1
2
D
=
2.014102
u
^2_1\mathrm D=2.014102\,\text u
1
2
D
=
2.014102
u
,
1
3
T
=
3.016049
u
^3_1\mathrm T=3.016049\,\text u
1
3
T
=
3.016049
u
,
2
4
H
e
=
4.002603
u
^4_2\mathrm He=4.002603\,\text u
2
4
H
e
=
4.002603
u
,
n
=
1.008665
u
n=1.008665\,\text u
n
=
1.008665
u
. Taking
1
u
=
931.5
MeV
/
c
2
1\,\text u = 931.5\,\text{MeV}/c^2
1
u
=
931.5
MeV
/
c
2
, calculate the energy released per reaction. (a)
8.8
MeV
8.8\, \text{MeV}
8.8
MeV
(b)
35.2
MeV
35.2\, \text{MeV}
35.2
MeV
(c)
17.6
MeV
17.6\, \text{MeV}
17.6
MeV
(d)
14.1
MeV
14.1\, \text{MeV}
14.1
MeV
Related theory
Mass-Energy Equivalence
Nuclear Fusion
Nuclear Reactions
Nuclear physics
Atomic Structure
Nuclear fusion (stars as energy sources)
Nuclei
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