The value of is

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

The value of ∫log⁡x(x+1)2dx\int \frac{\log x}{(x+1)^2} dx is (a) −log⁡xx+1+log⁡x−log⁡(x+1)\frac{-\log x}{x+1} + \log x - \log(x+1) (b) log⁡x(x+1)+log⁡x−log⁡(x+1)\frac{\log x}{(x+1)} + \log x - \log(x+1) (c) log⁡xx+1−log⁡x−log⁡(x+1)\frac{\log x}{x+1} - \log x - \log(x+1) (d) −log⁡xx+1−log⁡x−log⁡(x+1)\frac{-\log x}{x+1} - \log x - \log(x+1)

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