CBSE

MATHEMATICS · Multi-part · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Prove that (i) sin⁡2π6+cos⁡2π3−tan⁡2π4=−12\sin^2 \frac{\pi}{6} + \cos^2 \frac{\pi}{3} - \tan^2 \frac{\pi}{4} = -\frac{1}{2} (ii) 2sin⁡2π6+csc⁡27π6cos⁡2π3=322\sin^2 \frac{\pi}{6} + \csc^2 \frac{7\pi}{6} \cos^2 \frac{\pi}{3} = \frac{3}{2} (iii) cot⁡2π6+csc⁡5π6+3tan⁡2π6=6\cot^2 \frac{\pi}{6} + \csc \frac{5\pi}{6} + 3 \tan^2 \frac{\pi}{6} = 6 (iv) 2sin⁡23π4+2cos⁡2π4+2sec⁡2π3=102\sin^2 \frac{3\pi}{4} + 2\cos^2 \frac{\pi}{4} + 2\sec^2 \frac{\pi}{3} = 10

Related theory

Browse the problem library