A particular fission reaction can be represented as
92235U+01n⟶56141Ba+3692Kr+301n
The following atomic masses are provided:
235U=235.0439299u, 1n=1.0086650u, 141Ba=140.914411u, 92Kr=91.926156u.
Take 1u=931MeV and Avogadro’s number NA=6.02×1023mol−1.
(a) Calculate the mass defect for one fission event.
(b) Determine the energy released per fission in MeV.
(c) Find the total energy released when 1mol of 235U undergoes complete fission as above.