If and , where and , then is equal…

MATHEMATICS · Single correct · CBSE · Mathematics · Complex Numbers and Quadratic Equations · Complex Numbers and Quadratic Equations

Problem

If 1−ix1+ix=a−ib\frac{1-ix}{1+ix}=a-ib and a2+b2=1a^2+b^2=1, where a,b∈Ra,b\in\mathbb{R} and i=−1i=\sqrt{-1}, then xx is equal to (1) 2a(1+a)2+b2\frac{2a}{(1+a)^2+b^2} (2) 2b(1+a)2+b2\frac{2b}{(1+a)^2+b^2} (3) 2a(1+b)2+a2\frac{2a}{(1+b)^2+a^2} (4) 2b(1+b)2+a2\frac{2b}{(1+b)^2+a^2}

Related theory

Browse the problem library