A rubber ball approaches a level concrete floor with velocity components (toward the…

PHYSICS · Multi-part · CBSE · Physics · Force and Laws of Motion · Force and Laws of Motion

Problem

A 0.60 kg0.60\,\text{kg} rubber ball approaches a level concrete floor with velocity components vx=+3.0 m s−1v_x = +3.0\,\text{m}\,\text{s}^{-1} (toward the east) and vy=−8.0 m s−1v_y = -8.0\,\text{m}\,\text{s}^{-1} (downward). After bouncing, the ball leaves the floor with vx=+3.0 m s−1v_x = +3.0\,\text{m}\,\text{s}^{-1} and vy=+6.0 m s−1v_y = +6.0\,\text{m}\,\text{s}^{-1}. The ball is in contact with the floor for 0.020 s0.020\,\text{s}. Air resistance is negligible. (a) Calculate the change in momentum of the ball, expressing your answer in vector component form. (b) Determine the magnitude of the impulse delivered to the ball by the floor. (c) Compute the magnitude of the average force the floor exerts on the ball during the bounce.

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