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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
e
2
x
1
+
sin
2
x
1
+
cos
2
x
d
x
=
\int e^{2x} \frac{1 + \sin 2x}{1 + \cos 2x}\,dx =
∫
e
2
x
1
+
c
o
s
2
x
1
+
s
i
n
2
x
d
x
=
(a)
e
2
x
tan
x
+
c
e^{2x} \tan x + c
e
2
x
tan
x
+
c
(b)
e
2
x
+
cot
x
+
c
e^{2x} + \cot x + c
e
2
x
+
cot
x
+
c
(c)
e
2
x
tan
x
2
+
c
\frac{e^{2x} \tan x}{2} + c
2
e
2
x
t
a
n
x
+
c
(d)
e
2
x
cot
x
2
+
c
\frac{e^{2x} \cot x}{2} + c
2
e
2
x
c
o
t
x
+
c
Related theory
Integration by Parts
Integration Techniques
Standard algebraic integrals
Integrals of additional types
Integrals
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