At 25 °C the solubility product constant of is

CHEMISTRY · Single correct · AP · Chemistry · Equilibrium · Equilibrium

Problem

At 25 °C the solubility product constant of PbF2\text{PbF}_2 is Ksp=3.2×10−8K_{sp}=3.2\times10^{-8}. What is the molar solubility of PbF2\text{PbF}_2 in pure water at this temperature? (a) 5.1×10−3 M5.1\times10^{-3}\,\text{M} (b) 3.2×10−8 M3.2\times10^{-8}\,\text{M} (c) 2.0×10−3 M2.0\times10^{-3}\,\text{M} (d) 1.8×10−4 M1.8\times10^{-4}\,\text{M}

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