If are consecutive terms of a geometric progression with positive common ratio

MATHEMATICS · Single correct · CBSE · Mathematics · Sequences and Series · Sequences and Series

Problem

If 3x−2,  6,  12x+43x-2,\;6,\;12x+4 are consecutive terms of a geometric progression with positive common ratio, then xx equals (a) 23\dfrac{2}{3} (b) 35−13\dfrac{3\sqrt5-1}{3} (c) 1+356\dfrac{1+3\sqrt5}{6} (d) 1−356\dfrac{1-3\sqrt5}{6}

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