For a reaction at 298 K

CHEMISTRY · Subjective · A Level · Chemistry · Thermodynamics · Thermodynamics

Problem

For a reaction at 298 K, the standard free energy change is reported as +8.6 kJ mol−1+8.6\,\text{kJ mol}^{-1}. Assuming this value does not vary with temperature, determine the numerical value of the equilibrium constant at 400 K. Use R=8.314 J mol−1K−1R = 8.314\,\text{J mol}^{-1}\text{K}^{-1}.

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