MATHEMATICS · Multi-part · CBSE · Mathematics · Sequences and Series · Sequences and Series
Problem
For a GP with first term a and common ratio r(=1), let Sn denote the sum of its first n terms. A new GP is obtained by multiplying every term by a positive constant 7. Let Sn′ be the sum of the first n terms of this new progression.
(i) Show that Sn′−Sn=6Sn for every positive integer n.
(ii) If a=4 and r=23, determine the least positive integer n for which Sn′−Sn>10000.