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What are the solutions to the equation above?
MATHEMATICS · Single correct · CBSE · Mathematics · Quadratic Equations · Quadratic Equations
Problem 1 2 x 2 − 1 6 x − 1 3 = 0 \frac{1}{2}x^2 - \frac{1}{6}x - \frac{1}{3} = 0 2 1 x 2 − 6 1 x − 3 1 = 0
What are the solutions to the equation above?
(A) x = 1 x=1 x = 1 and x = − 2 3 x=-\frac{2}{3} x = − 3 2
(B) x = 1 6 − 23 36 x = \frac{1}{6} - \sqrt{\frac{23}{36}} x = 6 1 − 36 23 and x = 1 6 + 23 36 x = \frac{1}{6} + \sqrt{\frac{23}{36}} x = 6 1 + 36 23
(C) x = 2 x=2 x = 2 and x = − 4 3 x=-\frac{4}{3} x = − 3 4
(D) x = 1 6 − − 23 36 x = \frac{1}{6} - \sqrt{-\frac{23}{36}} x = 6 1 − − 36 23 and x = 1 6 + − 23 36 x = \frac{1}{6} + \sqrt{-\frac{23}{36}} x = 6 1 + − 36 23
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