What are the solutions to the equation above?

MATHEMATICS · Single correct · CBSE · Mathematics · Quadratic Equations · Quadratic Equations

Problem

12x2−16x−13=0\frac{1}{2}x^2 - \frac{1}{6}x - \frac{1}{3} = 0 What are the solutions to the equation above? (A) x=1x=1 and x=−23x=-\frac{2}{3} (B) x=16−2336x = \frac{1}{6} - \sqrt{\frac{23}{36}} and x=16+2336x = \frac{1}{6} + \sqrt{\frac{23}{36}} (C) x=2x=2 and x=−43x=-\frac{4}{3} (D) x=16−−2336x = \frac{1}{6} - \sqrt{-\frac{23}{36}} and x=16+−2336x = \frac{1}{6} + \sqrt{-\frac{23}{36}}

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