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PHYSICS · Single correct · AP · Physics 2: Algebra-based · Magnetism and Electromagnetism · Magnetism and Electromagnetism

Problem

Column IColumn IIColumn III
(i) Electron with v⃗=2E0B0x^\vec{v}=2\frac{E_0}{B_0}\hat{x}(i) E⃗=E0z^\vec{E}=E_0\hat{z}(p) B⃗=−B0x^\vec{B}=-B_0\hat{x}
(ii) Electron with v⃗=E0B0y^\vec{v}=\frac{E_0}{B_0}\hat{y}(ii) E⃗=−E0y^\vec{E}=-E_0\hat{y}(q) B⃗=B0x^\vec{B}=B_0\hat{x}
(iii) Proton with v⃗=0\vec{v}=0(iii) E⃗=−E0x^\vec{E}=-E_0\hat{x}(r) B⃗=B0y^\vec{B}=B_0\hat{y}
(iv) Proton with v⃗=2E0B0x^\vec{v}=2\frac{E_0}{B_0}\hat{x}(iv) E⃗=E0x^\vec{E}=E_0\hat{x}(s) B⃗=B0z^\vec{B}=B_0\hat{z}
In which case would the particle move in a straight line along the negative yy-axis, that is, along −y^-\hat{y}? (1) (II), (iii), (q) (2) (III), (ii), (r) (3) (IV), (ii), (s) (4) (III), (ii), (p)

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