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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
5
(
x
6
+
1
)
x
2
+
1
d
x
=
\int \frac{5(x^6 + 1)}{x^2 + 1}\,dx =
∫
x
2
+
1
5
(
x
6
+
1
)
d
x
=
(a)
5
(
x
7
+
x
)
tan
−
1
x
+
c
5(x^7 + x)\tan^{-1} x + c
5
(
x
7
+
x
)
tan
−
1
x
+
c
(b)
x
5
−
5
3
x
3
+
5
x
+
c
x^5 - \frac{5}{3}x^3 + 5x + c
x
5
−
3
5
x
3
+
5
x
+
c
(c)
3
x
4
−
5
x
2
+
15
x
+
c
3x^4 - 5x^2 + 15x + c
3
x
4
−
5
x
2
+
15
x
+
c
(d)
5
tan
−
1
(
x
2
+
1
)
+
log
(
x
2
+
1
)
+
c
5\tan^{-1}(x^2 + 1) + \log(x^2 + 1) + c
5
tan
−
1
(
x
2
+
1
)
+
lo
g
(
x
2
+
1
)
+
c
Related theory
Antiderivatives
Integration Techniques
Standard algebraic integrals
Integrals of additional types
Integrals
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