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The solubility–product constant for at 25 °C is
CHEMISTRY · Subjective · AP · Chemistry · Equilibrium · Equilibrium
Problem
The solubility–product constant for
A
g
B
r
AgBr
A
g
B
r
at 25 °C is
K
s
p
=
5.0
×
10
−
13
K_{sp}=5.0\times10^{-13}
K
s
p
=
5.0
×
1
0
−
13
. Calculate the molar solubility of
A
g
B
r
AgBr
A
g
B
r
in a solution that already contains
0.020
M
B
r
−
0.020\,\text{M}\;Br^-
0.020
M
B
r
−
. Report your answer in mol L
−
1
^{-1}
−
1
to two significant figures.
Related theory
Equilibrium
Chemical Equilibrium
Solubility product
Solubility Equilibria
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