Polonium emits particles and is converted into lead

PHYSICS · Subjective · CBSE · Physics · Nuclei · Nuclei

Problem

Polonium (84210Po)\left({}^{210}_{84}\text{Po}\right) emits 24He{}^{4}_{2}\text{He} particles and is converted into lead (82206Pb)\left({}^{206}_{82}\text{Pb}\right). This reaction is used for producing electric power in a space mission. 210Po{}^{210}\text{Po} has a half-life of 138.6138.6 days. Assuming an efficiency of 10%10\% for the thermoelectric machine, how much 210Po{}^{210}\text{Po} is required to produce 1.2×107 J1.2\times10^7\,\text{J} of electric energy per day at the end of 693693 days? Also find the initial activity of the material. Masses of nuclei: 210Po=209.98264 amu,206Pb=205.97440 amu,24He=4.00260 amu{}^{210}\text{Po}=209.98264\,\text{amu},\quad{}^{206}\text{Pb}=205.97440\,\text{amu},\quad{}^{4}_{2}\text{He}=4.00260\,\text{amu} 1 amu=931 MeV/c2andNA=6×1023 mol−1.1\,\text{amu}=931\,\text{MeV}/c^2\quad\text{and}\quad N_A=6\times10^{23}\,\text{mol}^{-1}.

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