For a certain metal

PHYSICS · Single correct · CBSE · Physics · Dual Nature of Radiation and Matter · Dual Nature of Radiation and Matter

Problem

For a certain metal, a graph of stopping potential V0V_0 versus frequency ν\nu yields a straight line with slope 4.14×10−15 V s4.14\times10^{-15}\,\text{V s}. Taking e=1.6×10−19 Ce=1.6\times10^{-19}\,\text{C}, calculate Planck’s constant hh. (a) 4.14×10−34 J s4.14\times10^{-34}\,\text{J s} (b) 6.63×10−34 J s6.63\times10^{-34}\,\text{J s} (c) 1.04×10−33 J s1.04\times10^{-33}\,\text{J s} (d) 6.63×10−35 J s6.63\times10^{-35}\,\text{J s}

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