The line is a normal to the ellipse

MATHEMATICS · Single correct · AP · AP Precalculus · Functions with Parameters, Vectors, and Matrices · Functions with Parameters, Vectors, and Matrices

Problem

The line 5x−3y=825x - 3y = 8\sqrt{2} is a normal to the ellipse x225+y29=1\frac{x^2}{25} + \frac{y^2}{9} = 1 . If θ′\theta' be eccentric angle of the foot of this normal, then θ′\theta' is equal to (1) π6\frac{\pi}{6} (2) π4\frac{\pi}{4} (3) π3\frac{\pi}{3} (4) π2\frac{\pi}{2}

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